ASPToday ASP Tip of Day for 17 April 2001, by Ian Vink

Return the folder of the current ASP file being accessed.

set fs = server.createObject("scripting.fileSystemObject")

Full_ASP_FILE_PATH = server.mapPath(request.serverVariables("PATH_INFO"))

PATH_ONLY = fs.getParentFolderName(Full_ASP_FILE_PATH)

response.write "This ASP page is being run in the folder: " & PATH_ONLY

Labels: ASP

This entry was posted on Tuesday, April 17, 2001 at 5:49 PM.